0.25x^2=106

Solution for 0.25x^2=106 equation:

0.25x^2=106

We move all terms to the left:

0.25x^2-(106)=0

a = 0.25; b = 0; c = -106;
Δ = b2-4ac
Δ = 02-4·0.25·(-106)
Δ = 106
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{106}}{2*0.25}=\frac{0-\sqrt{106}}{0.5}
=-\frac{\sqrt{}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{106}}{2*0.25}=\frac{0+\sqrt{106}}{0.5}
=\frac{\sqrt{}}{0.5}
$